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0.5x^2-7.5x+8=0
a = 0.5; b = -7.5; c = +8;
Δ = b2-4ac
Δ = -7.52-4·0.5·8
Δ = 40.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.5)-\sqrt{40.25}}{2*0.5}=\frac{7.5-\sqrt{40.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.5)+\sqrt{40.25}}{2*0.5}=\frac{7.5+\sqrt{40.25}}{1} $
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